A gas at pressure 912 mm of hg has volume of 450 cm3 what will be volume at 0.4 atm
Ans
1023K
1026000
To find the volume of a gas at a different pressure, we can use the combined gas law, which states:
(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂
Where:
P₁ and P₂ are the initial and final pressures,
V₁ and V₂ are the initial and final volumes, and
T₁ and T₂ are the initial and final temperatures.
In this case, we have:
P₁ = 912 mmHg
V₁ = 450 cm³
We need to convert the pressure from mmHg to atm, since the given pressure is in mmHg and the required pressure is in atm. The conversion is as follows:
1 atm = 760 mmHg
So, we can convert the initial pressure as follows:
P₁ = 912 mmHg / 760 mmHg/atm = 1.2 atm
Now, we have:
P₁ = 1.2 atm
V₁ = 450 cm³
P₂ = 0.4 atm
V₂ = ?
We can rearrange the combined gas law formula to solve for V₂:
V₂ = (P₂ * V₁ * T₁) / (P₁ * T₂)
Since the temperature is not given, we can assume that the temperature remains constant. Therefore, T₁ = T₂. This means that we can eliminate the temperature terms from the equation, giving us:
V₂ = (P₂ * V₁) / P₁
Now, we can plug in the values and solve for V₂:
V₂ = (0.4 atm * 450 cm³) / 1.2 atm
V₂ = 150 cm³
Therefore, the volume of the gas at 0.4 atm would be 150 cm³.