Bob heads out into a lake at an angle of 41◦ with respect to the shore.
If his boat is capable of a speed of 1.7 m/s, how far from land will he be in 7 min and 17 s ?
Answer in units of m.
To find the distance from land that Bob will be, we can use the formula:
distance = speed × time
First, let's convert the given time of 7 minutes and 17 seconds into seconds. Since 1 minute is equal to 60 seconds, we have:
7 minutes × 60 seconds/minute = 420 seconds
7 minutes and 17 seconds = 420 seconds + 17 seconds = 437 seconds
Now, we can calculate the distance from land using the given speed of 1.7 m/s and the converted time of 437 seconds:
distance = 1.7 m/s × 437 seconds
distance ≈ 741.9 m
Therefore, Bob will be approximately 741.9 meters from the shore.
To find how far from land Bob will be in 7 minutes and 17 seconds, we first need to calculate how far he will travel in that time.
We know that Bob's boat is capable of a speed of 1.7 m/s. To find the distance he will travel, we need to multiply his speed by the time he will be traveling.
First, we need to convert 7 minutes and 17 seconds to seconds. There are 60 seconds in a minute, so 7 minutes is equal to 7 * 60 = 420 seconds. Adding the additional 17 seconds, we have a total of 420 + 17 = 437 seconds.
Now we can calculate the distance traveled using the formula:
distance = speed * time.
Plugging in the values, we get:
distance = 1.7 m/s * 437 s.
Calculating this multiplication, we find that distance = 743.9 m.
Therefore, Bob will be approximately 743.9 meters from land in 7 minutes and 17 seconds.
V = 1.7m/s[41o].
d = 1.7m/s * 437s *sin41 = 487.4 m.