1) A television tower is 160 feet high and an observer is 120 feet from the base of the tower. Find, to the nearest degree, the angle of elevation of the top of the tower from the point of observation.
2) A vertical pole 22 meters tall casts a shadow 16 meters long on level ground. Find, to the nearest degree, the measure of the angle of elevation of the sun.
3) From the top of a cliff 90 feet high, the angle of depression of an object on the ground measures 40 degrees. Find, to the nearest hundredth, the distance from the object to the base of the cliff.

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  1. For each of them , make a sketch
    In each case you will get a right-angled triangle
    You MUST know the basic trig ratios in terms of
    opposite, adjacent, and hypotenuse.
    e.g. tanØ = opposite/adjacent

    1) so we have tanØ = 160/120 = 4/3
    Make sure your calculator is set to 'degrees'
    ( the D in your DRG button, mine shows DEG in small print at the top)

    you should get 53.130...
    so to the nearest degree, the angle is 53

    2) identical question

    3) your text, notes, or your teacher should have explained the meaning of "angle of depression" and "angle of elevation"
    try this one, let me know what you get.

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