A ninety kilogram sofa is being pushed by four meters to the other side of a hall. After an initial push the sofa is pushed with a 600 N force. In this case, 0.6 is the coefficient of kinetic friction. What would be the magnitude and direction of the frictional force on the sofa?
Is this 529.74? The diagram shows the sofa being pushed toward the left, so is the direction of the frictional force to the right?
If it is moving to the left, the frictional force is pushing right.
0.6 * 90 * 9.81
yes, looks about right but stick to 3 significant figures.
To answer this question, we can use the equation for the frictional force:
Frictional force = coefficient of friction * normal force
The normal force is equal to the weight of the object, which is the mass multiplied by the acceleration due to gravity (9.8 m/s^2).
First, calculate the normal force:
Normal force = mass * acceleration due to gravity
Normal force = 90 kg * 9.8 m/s^2
Normal force = 882 N
Now, we can find the frictional force:
Frictional force = coefficient of friction * normal force
Frictional force = 0.6 * 882 N
Frictional force = 529.2 N
So, the magnitude of the frictional force on the sofa is 529.2 N.
The direction of the frictional force depends on the direction of the pushing force. In this case, since the sofa is being pushed to the left, the frictional force acts in the opposite direction (to the right) to oppose the motion. Therefore, the direction of the frictional force is to the right.