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Find the coordinates of the points of intersection of the graph of y=13−x with the axes and compute the area of the right triangle formed by this line and coordinate axes.

can u guys plz find answer + explain this problem is really hard and confusing 2 me

13 answers Show only top 10 answers

(0,13)

(13,0)
and (0,0) completes triangle

that is half a 13 by 13 square
area = 169/2

Thank you Damon too

thanks Damon

Thank you so much, I needed this, :)

thanks damon

im 5 years late lol

Thank you Damon

In case you thought Damon's answer was wrong, the x intercept is 13, 0 and the y intercept is 0, 13. The area of the right triangle is 169/2

same lol

X intercept-13,0

Y intercept-0,13
Area: 169/2

I’m 4 years late lol

hey, everyone, damon is wrong! a. is (5,3) and b. is (2,-6)! so yeah!

Wow, guess I'm 4 years late! Haha

x intercept- (13,0)

y intercept-(0,13)
area of the right triangle- (13*13)/2=84.5

Did you know?

Did you know that when given a line equation like y=13−x, you can find the points where the line intersects with the x and y axes? These points are known as the coordinates of intersection. By substituting y=0 into the equation, you can solve for the x-coordinate of the point of intersection with the x-axis. Similarly, substituting x=0 will give you the y-coordinate of the point of intersection with the y-axis. Once you have found these coordinates, you can use them to form a right triangle with the line and the coordinate axes. The base of the right triangle will be the x-coordinate of the point of intersection with the x-axis, the height will be the y-coordinate of the point of intersection with the y-axis, and the hypotenuse will be the line itself. To find the area of this right triangle, you can use the formula: Area = (1/2) * base * height. So, by plugging in the values for the base and height that you found, you can easily compute the area of the right triangle.