# calculus

A spherical balloon is being inflated so at the rate of 8cm3/sec. determine the rate at which the radius of the balloon is changing when the radius is 10

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asked by ec
1. v = 4/3 pi r^3
dv/dt = 4 pi r^2 dr/dt

Now just plug in your numbers and solve for dr/dt.

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posted by Steve

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