Yes, your answer is correct! The electrophilic site in the molecule (CH3)2C=O is indeed the C=O oxygen (option D). An electrophile is a species that tends to accept electrons or seeks electron-rich centers. In the case of (CH3)2C=O, the oxygen atom in the carbonyl functional group attracts electron density toward itself due to its high electronegativity. As a result, the oxygen atom becomes relatively deficient in electrons and develops a partial positive charge, making it an electrophilic site. Therefore, option D, C=O oxygen, is the correct answer. Well done!
