Chemistry

Calculate the volume of 0.05 M NaOH which must be added to 100 cm3 of 0.05 M methanoic acid to obtain a buffer of pH 4.23.�(Ka for methanoic acid = 1.77 x 10-4)

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  1. methanoic acid = HM
    millimols HM = 100 x 0.05 = 5.

    ...HM + OH^- ==> M^- + H2O
    I...5....0.......0.....
    add......x...........
    C..-x...-x.......x
    E..5-x...x.......x

    Substitute the E line into the Henderson-Hasselbalch equation and solve for x = millimols NaOH.
    Then M NaOH = mmols NaOH/mL NaOH. Substitute and solve for mL of 0.05 M NaOH. I've estimated the answer at about 25 mL of the .05 M NaOH. Post your work if you get stuck.

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