A stock solution of sulfuric acid must be diluted by adding 25.0mL of 7.50M H2SO4 to enough water to make 500mL of diluted soultion. What is the concentration of the diluted solution?
mL1 x M1 = mL2 x M2
25.0 x 7.50 = 500 mL x M2
To find the concentration of the diluted solution, we can use the formula:
C1V1 = C2V2
Where:
C1 = Initial concentration of the stock solution
V1 = Initial volume of the stock solution
C2 = Final concentration of the diluted solution
V2 = Final volume of the diluted solution
In this case, we are given:
C1 = 7.50 M (concentration of the stock solution)
V1 = 25.0 mL (volume of the stock solution)
V2 = 500 mL (volume of the diluted solution)
Let's substitute the given values into the formula and solve for C2:
(7.50 M)(25.0 mL) = C2(500 mL)
Now we can solve for C2:
C2 = (7.50 M)(25.0 mL) / 500 mL
C2 = (7.50)(0.05)
C2 = 0.375 M
Therefore, the concentration of the diluted solution is 0.375 M.
To find the concentration of the diluted solution, we can use the equation:
C1V1 = C2V2
Where:
C1 = initial concentration of the stock solution
V1 = volume of the stock solution
C2 = final concentration of the diluted solution
V2 = final volume of the diluted solution
In this case, we are given:
C1 = 7.50 M
V1 = 25.0 mL
V2 = 500 mL
Let's solve for C2:
C1V1 = C2V2
7.50 M * 25.0 mL = C2 * 500 mL
To simplify the calculation, let's convert mL to L:
7.50 M * 0.025 L = C2 * 0.5 L
0.1875 mol = C2 * 0.5 L
Dividing both sides by 0.5 L:
0.1875 mol / 0.5 L = C2
C2 = 0.375 M
Therefore, the concentration of the diluted solution is 0.375 M.