Roberto has 20 crayons 12 are red. the rest are blue and yellow.
he has 2 more blue than yellow. how many blue crayons does he have?
20 - 12 = 8 blue and yellow
1, 7
2, 6
3, 5
4, 4
Let's solve the problem step by step.
Step 1: Add the number of red, blue, and yellow crayons to find the total number of crayons Roberto has.
Red crayons: 12
Blue crayons: ?
Yellow crayons: ?
Total crayons: 20
Step 2: Since the total number of crayons Roberto has is 20, the sum of the red, blue, and yellow crayons should equal 20.
12 + blue crayons + yellow crayons = 20
Step 3: We know that the quantity of blue crayons is 2 more than the yellow crayons (blue = yellow + 2). Let's substitute this information into equation (2).
12 + (yellow + 2) + yellow = 20
Step 4: Simplify the equation by combining like terms.
12 + 2yellow + 2 = 20
Step 5: Combine like terms again.
2yellow + 14 = 20
Step 6: Isolate the term with the variable (2yellow) by subtracting 14 from both sides of the equation.
2yellow = 20 - 14
2yellow = 6
Step 7: Divide both sides of the equation by 2 to solve for the value of yellow.
yellow = 6 / 2
yellow = 3
Step 8: Substitute the value of yellow (3) into the equation for blue crayons (blue = yellow + 2).
blue = 3 + 2
blue = 5
Therefore, Roberto has 5 blue crayons.
To find out how many blue crayons Roberto has, we first need to determine the number of yellow crayons he has.
We know that Roberto has a total of 20 crayons and 12 of them are red. This means that the number of blue and yellow crayons combined is 20 - 12 = 8.
Now, let's assume Roberto has y yellow crayons. According to the problem, he has 2 more blue crayons than yellow crayons. Therefore, the number of blue crayons he has is y + 2.
Since the total number of blue and yellow crayons is 8, we can set up an equation using the information above:
y + (y + 2) = 8
Simplifying the equation, we get:
2y + 2 = 8
Subtracting 2 from both sides of the equation, we get:
2y = 6
Dividing both sides of the equation by 2, we find:
y = 3
So Roberto has 3 yellow crayons. And since he has 2 more blue crayons than yellow crayons, he has 3 + 2 = 5 blue crayons.
Therefore, Roberto has 5 blue crayons.