# maths need help

determine arcsinh(2+i) in form of a+bi
thanks

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1. I'm sure you know that

arcsinh(z) = log(z+โ(1+z^2))
so,
arcsinh(2+i) = log(2+i + โ(4+2i))
= log(4.058 + 1.486i)

Now log(z) = log(x+yi)
= log(โ(x^2+y^2) + i arctan(y/x)

So, plug in your z value above and crank it out.

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2. 👎
2. google arcsinh to get the definition I gave

google complex logarithm to find how to evaluate it.

Surely you have enough keywords to do some research yourself. I didn't know that stuff either, but I know how to search for it.

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