# Math

Find the last two digits of the number 11^2016 .

I need to figure out how to hand do this and show all my work. Help pls

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1. Start a table of the powers of 11
n 11^n
1 11
2 121
3 1331
4 14641

The last 2 digits just cycle through
11
21
31
...
91
01
11
21
...
So, 11^2016 ends in 61

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