A player shoots a basketball from a height of 6 feet. The equation, h = -16t 2 + 25t + 6, gives the height, h , of the basketball after t seconds. Describe the height, rounded to the nearest tenth of a foot, of the basketball after 1.5 seconds, assuming no other player touches the ball.
did you sub in your given value of t ?
i.e.
how about evaluating
height = -16(1.5)^2 + 25(1.5) + 6
follow the instructions regarding rounding.
To find the height of the basketball after 1.5 seconds, we need to substitute the value of t into the equation h = -16t^2 + 25t + 6.
Let's calculate it step-by-step:
1. Substitute t = 1.5 into the equation:
h = -16(1.5)^2 + 25(1.5) + 6
2. Simplify the equation by squaring 1.5 and multiplying the terms:
h = -16(2.25) + 37.5 + 6
h = -36 + 37.5 + 6
h = 7.5
3. Round the height to the nearest tenth of a foot:
The height of the basketball after 1.5 seconds is approximately 7.5 feet.
Therefore, the height of the basketball after 1.5 seconds, rounded to the nearest tenth of a foot, is 7.5 feet.
To find the height of the basketball after 1.5 seconds, we need to substitute the value of t = 1.5 into the equation h = -16t^2 + 25t + 6.
Let's calculate it step by step:
Step 1: Substitute t = 1.5 into the equation.
h = -16(1.5)^2 + 25(1.5) + 6
Step 2: Simplify the equation using the order of operations (parentheses, exponents, multiplication/division, and addition/subtraction).
h = -16(2.25) + 37.5 + 6
h = -36 + 37.5 + 6
h = 7.5 + 6
h = 13.5
Therefore, the height of the basketball after 1.5 seconds is approximately 13.5 feet.