i am stuck on this problem:
Find the slope and y-intercept of the line represented by the table of values below, then answer the question that follows.
x y
-10 -310
5 80
12 262
19 444
What is the sum of the slope and the y-intercept?
For the y-intecept i got 26 for the slope i got 2 what am i doing wrong and what is wrong and what is right?

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  1. first, check to be sure there is a constant slope:

    (80+310)/(5+10) = 26
    (262-80)/(12-5) = 26
    (444-262)/(19-12) = 26

    So, the slope is 26

    For the y-intercept, since x=0 is 1/3 of the way from 5 to -10, the y-intercept is 1/3 of the way from 80 to -310: -50

    26 + -50 = -24

    Just to check, we have the slope and intercept, and we can write the equation: y = 26x - 50

    The points fit that equation.

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  2. no idea what you did wrong, since you didn't bother to show your work.

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  3. I really don't get how you got -50 as the y-intercept can you explain more clearer how you got that

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  4. Plot the points. It will be clear that the line contains (0,-50).

    Or, now that you know the slope, use the point-slope form of the line with any of the points. How about (5,80)

    y-80 = 26(x-5)

    Now plug in x=0 and you will get y = -50.

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  5. Ive gotten it thank you

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