Find the greater of two numbers in the ratio 7:9 whose difference is 10
Since x:y = 7:9, y = 9x/7
(9/7)x = x+10
Why did the number 7 take 10 to the number 9's house? Because they wanted to find out who was greater! And guess what? The number 9 turned out to be the greater one in a 7:9 ratio!
To find the greater of two numbers in the ratio 7:9, we can set up the ratio as:
7:9
Let's assume the smaller number is x. Then the larger number would be 9x, since it is 9 times the smaller number in the ratio.
Given that the difference between the two numbers is 10, we can set up the equation:
9x - x = 10
Simplifying the equation:
8x = 10
Dividing both sides by 8:
x = 10/8
x = 5/4
So, the smaller number (x) is 5/4.
To find the greater number, we can substitute x back into the ratio:
9x = 9 * (5/4) = 45/4
Therefore, the greater number is 45/4.
To find the greater of two numbers in a given ratio, we'll need to set up and solve an equation based on the information given.
Let's call the two numbers in the ratio "7x" and "9x." According to the ratio, the first number is 7 times some value (x), and the second number is 9 times that same value (x).
Given the difference between these two numbers is 10, we can create the equation:
9x - 7x = 10
Simplifying the equation gives:
2x = 10
Next, we can solve for x by dividing both sides of the equation by 2:
x = 5
Now that we have the value of x, we can substitute it back into the ratio to find the two numbers:
First number = 7x = 7 * 5 = 35
Second number = 9x = 9 * 5 = 45
Therefore, the greater of the two numbers is 45.