X Y & Z are 3 whole numbers that in total add up to 1750.
X + Y and Z = 1750
X is 4 times greater than Y.
Z is 2 times greater than Y.
Calculate the 3 numbers X Y & Z?
Thanks for your answer, but no there is no typos.
I paraphrased the question, but here it is in full, as per the paper
X Y and Z each stand for a whole number.
They add together to make 1750
X + Y and Z =1750
X is four times as big as Y
Z is twice as big as Y
Calculate the numbers X Y and Z.
X + Y + Z = 1750
x = 4Y
Y = 2Y
4Y + Y + 2Y = 1750
However, that does not come out exactly to whole numbers. Do you have any typos? It would seem that the zero is extraneous.
x = 1000
y = 250
z = 500
To solve this problem, we'll use algebraic equations based on the given information. Let's start by assigning variables to the unknown numbers:
Let Y be the value of Y.
Then, X will be 4 times greater than Y, so X = 4Y.
And Z will be 2 times greater than Y, so Z = 2Y.
Now we can set up the equation based on the total sum:
X + Y + Z = 1750.
Substituting the values of X and Z in terms of Y, we get:
4Y + Y + 2Y = 1750.
Combining like terms, we simplify the equation:
7Y = 1750.
Now we can solve for Y by dividing both sides of the equation by 7:
Y = 1750 / 7
Y = 250.
Now that we have the value of Y, we can find X and Z:
X = 4Y = 4 * 250 = 1000.
Z = 2Y = 2 * 250 = 500.
So the three numbers are:
X = 1000,
Y = 250, and
Z = 500.