Math

In an automobile race, the rate of one car was 120 mi/hr and the rate of another was 105 mi/hr. If the faster car finished the race 20 minutes before the slower one, what was the distance of the race?

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  1. since distance = speed * time,

    120t = 105(t + 1/3)

    solve for t, then find the distance

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  2. In an automobile race, the rate of one car was 120 mi/hr and the rate of another was 105 mi/hr. If the faster car finished the race 20 minutes before the slower one, what was the distance of the race?

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