Algebra

An ordinary plane leaves an airport and flies due west at 180kph. Two hours later, a jet leaves the same airport and flies due west at 900kph. How far from the airport will the jet overtake the ordinary plane?

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  1. key point:
    at the "overtaking" they both will have gone the same distance in a time 2 hrs apart.

    let the time taken by the jet be t hrs
    then the time taken by the small plane be t+2 hrs

    900t = 180(t+2)
    900t = 180t + 360
    720t = 360
    t = 1/2

    then 900t = 450
    they will be together after 450 km

    check:
    jet went 900(1/2) = 450 km
    small plane went 180(2 1/2)
    = 180(5/2) = 450 km
    Ok !

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