Solve 2m^2+5m-20=0 using quadratic formula
m = [-5±√(5^2+4*2*20)]/4
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To solve the quadratic equation 2m^2 + 5m - 20 = 0 using the quadratic formula, you can follow these steps:
Step 1: Identify the values of coefficients a, b, and c in the equation:
- In this equation, a = 2, b = 5, and c = -20.
Step 2: Substitute these values into the quadratic formula:
- The quadratic formula is given by:
m = (-b ± √(b^2 - 4ac)) / (2a)
- Substituting the values of a, b, and c into the formula, we get:
m = (-(5) ± √((5)^2 - 4(2)(-20))) / (2(2))
Step 3: Simplify the equation inside the square root:
- Simplifying the expression within the square root:
m = (-5 ± √(25 + 160)) / 4
m = (-5 ± √185) / 4
Step 4: Evaluate the two possible values of m:
- To find the two possible solutions, we calculate both the positive and negative values for the square root expression:
m1 = (-5 + √185) / 4 and m2 = (-5 - √185) / 4
Therefore, the solutions to the quadratic equation 2m^2 + 5m - 20 = 0 using the quadratic formula are:
- m1 = (-5 + √185) / 4
- m2 = (-5 - √185) / 4