Evaluate the function.
h(a) = 2^a+1; Find h(a - 4)
just make the substitution:
h(a-4) = 2^(a-4)+1 = 2^a/16 + 1
or, if you were careless with parentheses,
h(a-4) = 2^(a-4+1) = 2^(a-3) = 2^a/8
h(a) = 2^a+1; Find h(a - 4)
h(a-4) = 2^(a-4)+1 = 2^a/16 + 1
or, if you were careless with parentheses,
h(a-4) = 2^(a-4+1) = 2^(a-3) = 2^a/8