During the experiment, 100ml will be required to prepare 0.5M solution of NaNO3. Calculate the mass of NaNO3 in grams that will be required.
To calculate the mass of NaNO3 required to prepare a 0.5M solution, you need to know the molar mass of NaNO3 and use the formula:
Mass (g) = Molarity (mol/L) * Volume (L) * Molar mass (g/mol)
First, let's find the molar mass of NaNO3:
Na – Sodium – atomic mass = 22.99 g/mol
N – Nitrogen – atomic mass = 14.01 g/mol
O – Oxygen – atomic mass = 16.00 g/mol
So, the molar mass of NaNO3 = 22.99 + 14.01 + (16.00 * 3) = 85.00 g/mol
Now, we can use the formula to calculate the mass of NaNO3 required:
Mass (g) = 0.5 mol/L * 0.1 L * 85.00 g/mol
Mass (g) = 0.5 * 0.1 * 85.00
Mass (g) = 4.25 grams
Therefore, to prepare a 0.5M solution of NaNO3, you will need 4.25 grams of NaNO3.