MATH

THE 14TH TERM OF AP IS 96 WHILE THE 25TH TERM IS 173 FIND THE
A.19TH TERM
B.SUM OF 13TH AND 56TH TERM

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  1. TN=A+(N-1)D
    T19=5+(19-1)7=5+18(7)
    =15+126=T19=131

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  2. http://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html

    Xn = a +(n-1)d

    96 = a + 13 d
    173 = a + 24 d
    ---------------
    -77 = -11 d
    d = 7
    then a = 96 - 13*7 = 5
    so
    X19 = 5 + 18*7 = 131 etc

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  3. LOL, yes :) good

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  4. 173=a+24d
    96=a+13d
    77=11d
    d=7
    96=a+13×7
    96=a+91
    a=5
    19th term = a+18d
    5+18×7
    =131

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  5. The14th term of an ap is 96 while the 25th term is 173 find the (a)the19th term (b)sum of 13th and 5th term (c)product of

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  6. Maths

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  7. Nothing

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  8. The forth term

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  9. Tn=a+(n-1)d
    93=a+(14-1)d
    96=a+13d---eqn(i)
    173=a+(25-1)d
    173=a+24d---eqn(ii)
    a+13d=96
    a+24d=173
    11d=77
    d=7 a+13(7)=96
    a+91=96
    a=96-1
    a=5
    (a) tn=5+(19-1)7
    T19=5+(18)7
    T19=5+126
    T19=131

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  10. 😊😊😊😊😀😀😀😀😘😘😘😘😘😘 excellent

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