# MATH

THE 14TH TERM OF AP IS 96 WHILE THE 25TH TERM IS 173 FIND THE
A.19TH TERM
B.SUM OF 13TH AND 56TH TERM

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1. TN=A+(N-1)D
T19=5+(19-1)7=5+18(7)
=15+126=T19=131

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2. http://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html

Xn = a +(n-1)d

96 = a + 13 d
173 = a + 24 d
---------------
-77 = -11 d
d = 7
then a = 96 - 13*7 = 5
so
X19 = 5 + 18*7 = 131 etc

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3. LOL, yes :) good

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4. 173=a+24d
96=a+13d
77=11d
d=7
96=a+13×7
96=a+91
a=5
19th term = a+18d
5+18×7
=131

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5. The14th term of an ap is 96 while the 25th term is 173 find the (a)the19th term (b)sum of 13th and 5th term (c)product of

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6. Maths

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7. Nothing

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8. The forth term

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9. Tn=a+(n-1)d
93=a+(14-1)d
96=a+13d---eqn(i)
173=a+(25-1)d
173=a+24d---eqn(ii)
a+13d=96
a+24d=173
11d=77
d=7 a+13(7)=96
a+91=96
a=96-1
a=5
(a) tn=5+(19-1)7
T19=5+(18)7
T19=5+126
T19=131

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10. 😊😊😊😊😀😀😀😀😘😘😘😘😘😘 excellent

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