calculus

Find
lim as (x,y) goes to (0,0) of
(e^(-x^2-y^2)-1)/(x^2+y^2).

  1. 0
  2. 4
asked by andre
  1. lim (e^-u^2-1)/u^2
    = lim (-2u e^-u^2)/2u = -1

    Now let u^2 = x^2+y^2

    1. 0
    posted by Steve

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