Let the function f be defined by f (x)= x+ l. If 2f(p)=20, what is the value of f (3p)?
if 2f(p)=20 then f(p)= 10
so,
f(3p)=3*10
f(3p)= 30
i hope this helps!
To find the value of f(3p), we need to first find the value of p from the equation 2f(p) = 20.
Given that f(x) = x + 1, we can substitute p into the function to find f(p):
f(p) = p + 1
Now let's solve the equation 2f(p) = 20:
2(p + 1) = 20
We can simplify this equation:
2p + 2 = 20
Next, subtract 2 from both sides of the equation:
2p = 20 - 2
2p = 18
To isolate p, divide both sides of the equation by 2:
p = 18 / 2
p = 9
Now that we have found the value of p, we can substitute it into the function f(x) to find f(3p):
f(3p) = 3p + 1
f(3p) = 3(9) + 1
f(3p) = 27 + 1
f(3p) = 28
Therefore, the value of f(3p) is 28.
To find the value of f(3p), we need to first find the value of p.
Given that 2f(p) = 20, we can substitute the function f(x) = x + 1 into this equation:
2(p + 1) = 20
Now let's solve for p:
2p + 2 = 20
2p = 20 - 2
2p = 18
p = 18/2
p = 9
Now that we have the value of p, we can find f(3p) by substituting p = 9 back into the function f(x):
f(3p) = f(3 * 9)
f(3p) = f(27) = 27 + 1 = 28
So the value of f(3p) is 28.