an object falls from the beach 45 meters above the water it falls directly into a boat which moves at a constant speed that was initially 12 meters from the point of impact when the object was released what was the speed of the boat
To find the speed of the boat, we need to consider the time it takes for the object to fall and reach the boat.
First, let's calculate the time it takes for the object to fall. We can use the equation of motion for free-falling objects:
s = ut + (1/2)at^2
Where:
s = distance (45 meters)
u = initial velocity (0 m/s as the object is released from rest)
a = acceleration due to gravity (-9.8 m/s^2, assuming downward as positive)
Given that the initial velocity is 0, the equation simplifies to:
s = (1/2)at^2
Plugging in the values:
45 = (1/2)(-9.8)t^2
Simplifying further:
90 = -4.9t^2
Dividing both sides by -4.9:
t^2 = -18.37
Since time cannot be negative, we know we made an error when solving for t. This means there is no real solution, and the object never actually reaches the boat. Therefore, the speed of the boat is irrelevant in this scenario.