A boxer is punching the heavy bag. The time of impact of the glove with the bag is 0.10 s. The mass of the glove and his hand is 3 kg. The velocity of the glove just before impact is 25 m/s. What is the average impact force exerted on the glove?
average force = change of momentum/time
= 3 * 25 / .1 Newtons
To calculate the average impact force exerted on the glove, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a). In this case, the mass of the glove and hand is given as 3 kg.
First, let's find the acceleration (a) experienced by the glove during the impact. We can do this by using the equation for average acceleration:
a = (vf - vi) / t
where vf is the final velocity, vi is the initial velocity, and t is the time taken.
Given that the time of impact (t) is 0.10 s and the initial velocity (vi) is 25 m/s, we can calculate the acceleration:
a = (0 - 25) m/s / 0.10 s = -250 m/s^2
Since the acceleration is negative, it means that the glove experienced a deceleration during impact.
Now, we can calculate the average impact force (F) using Newton's second law:
F = m * a
Substituting the given mass (m = 3 kg) and the calculated acceleration (a = -250 m/s^2), we get:
F = 3 kg * -250 m/s^2 = -750 N
The negative sign indicates that the force is acting in the opposite direction of the velocity (deceleration).
Therefore, the average impact force exerted on the glove is 750 Newtons (in the opposite direction of the motion).