physics

a car and a truck starts from rest at the same instant with the car is behind the truck initially at the same distance. the truck has a constant acceleration of 4 ft/s^2 and the car has an acceleration of 6 ft/s^2. the car overtake the truck after the truck travelled 150 ft.
a.at what time did the car overtakes the truck?
b. how far was the car behind the truck initially?
c. what is the velocity of each when they abreast?

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asked by teph
  1. a. 0.5*a*t^2 = 150. 0.5*4.6t^2 = 150, t = 8.1 s.

    b. 0.5a*t^2 = d + 150. a = 6 ft./s^2, t = 8.1s, d = ?.

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    posted by Henry

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