A car is at motion.It horns an hears the echo of the sound after 6 sec.find the speed of the car.
speed of sound=330m/s,there is unequal distance covered by the sound bcs the car was moving,then we should assume
Cont.d: -there is different time,let us use 4&2,4s for sound to go & 2s to come back,using : V=2D/T,find d using 4&2s.
Cont.d: in 4s we get 660m,& 2s,330m,therefore the speed of the car: D1-D2/T1-T2,where d1=large distance,t1=samE
You can try it with 5 and 1 second,you would get the same velocity
To find the speed of the car, we need to use the formula:
Speed = Distance / Time
In this case, we know that the time it takes for the sound to travel and return as an echo is 6 seconds. Since the sound has to travel twice the distance between the car and the object where it bounced off, we can consider the total distance traveled by the sound as the distance between the car and the object.
Let's assume the total distance traveled by the sound is 'd'. Since sound travels at a constant speed in air, we can express the total distance as:
d = speed of sound × time
Given that the time taken is 6 seconds, we can rewrite the equation as:
d = speed of sound × 6
Now, the total distance can also be represented as the distance traveled by the car during the time it takes for the sound to reach the object and return as an echo.
d = Speed of car × 6
By equating the two expressions for 'd', we have:
Speed of sound × 6 = Speed of car × 6
Dividing both sides by 6, we get:
Speed of sound = Speed of car
Therefore, the speed of the car is equal to the speed of sound, which is approximately 343 meters per second in dry air at 20°C.
Note: This assumes that the speed of sound remains constant throughout the calculation and there are no additional factors affecting the speed of the sound or the motion of the car.