In a competition, 5 points were awarded for each game won and 2 points were deducted for each game lost.A pupil attempted 15 games and got 54 points.How many games did the pupil win?
If w games were won, then 15-w were lost, so the points add up as
5w - 2(15-w) = 54
So, solve for w.
12 games won
Won-x
Lost-15-x
Points won=5x
Points lost=-2(15-x)=-30+2x
5x-30+2x=54
5x+2x=54+30
7x=84
X=12
Won games=12games
I like it...the methord given..is ok..thank you guyz
5w-2(15-w)=54
Very good this sum had given me a headache 👍👍👍👍
Let x be the no,of games won , game lost 15-x , point awarded, incase he win all,the game,he could have scored,15x5 =75,point penalized =75-54=21, penalty point 5awarded+2deducted=7point ,divide 21 by8=3=therefore he lost 3games and won 12games
12
12
good atempt
good
Good.
The method is very useful
Thanks so much aki. Headache kwisha.
Thanks gyz
Thanks you
I haven't understood the method kindly somebody to just explain it for me
Win=x
Loss=15-x
;....win will be 5×x
....loss... 2(15-x)
Sum of points... 54
Therefore (5×X)-2(15-X)=54
5X-30+2X=54
7X=54+30
7X=84....divide both side with 7...
X=12
Won...12
Lost...3
Win= +5pts
Lose= -2pts
Play= 15games
Total Points= 54pts
If Win= X ... Then, Lose= 15-X
Win= 5X Lose= -2(15-X) -30+2X
Win + Lose = 54
5X + (-30+2X) = 54 ...Collect the terms.
7X-30=54
7X=84 ...Divide both sides by 7.
X=12 Win (X) = 12
Therefore, Lose 15-X... =15-12
=3
5x-2x=54-30
=3x/3=24/3
X=8
I need the answer
Answer=6
won =12
Let the number of games won be x
To get what he lose we subtract the number of games won from 15
5{x} -2{15-x}=54
5x-30+ 2x=54
7x=84
x = 12
Lose=15-x
15-12
=3
The pupil won 12 games and lost 3 games.
5X+30-2X=54
5X-2X=54-30
3X/3=24/3
=5 X +30-2X=54
5X-2X=54-30
3X/3=24/3=
X=8
Let win be X
So loss will be 15-X
5*x+ 2(15-x)=54
5X+30-2X=54
3X+30-30=54-30
3X=24
X=8
So 8 games won
7games lost