Please help me solve this  PreCalc
Use identities to find the exact value of the trigonometric expression below.
1/cos2 * π/16  1/cot2 * π/16
PS: in words, the problem is, one divided by cosinesquared, then beside the cosinesquare (still in the denominator) is pi/16. Minus one divided by cotangentsquared, then beside the cotangentsquared (still in the denominator) is pi dived by 16.) please show steps so that I can learn this.
asked by
chizoba

let x = π/6 for easier typying
so your 1/cos2 * π/16  1/cot2 * π/16
= 1/cos^2 x  1/cot^2 x
= sec^2 x  tan^2 x
since sec^2 x = 1 + tan^2 x ,
= 1 + tan^2 x  tan^2 x
= 1posted by Reiny
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