Statistics
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Assume that women's heights are normally distributed with a mean given by mu equals 63.4 in, and a standard deviation given by sigma equals 1.8 in. Complete parts a and b. a. If 1 woman is randomly selected, find the
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Women’s heights are normally distributed with a mean of 63.6 in and a sd of 2 .5in. The US Army requires women’s heights to be between 58 in and 80 in. Find the percentage of women meeting that height requirement.
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Assume that women's heights are normally distributed with a mean=63.6 in. and standard deviation = 2.5 in. a) To be eligible for the US Marine Corps, a woman must have a height between 58 in. and 73 in. Find the percentage of
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Assume the heights of women are normally distributed with a mean given by 63.6 inches and a standard deviation given by 2.5 inches, the US Army requires women's height to be between 58 and 80 inches. Find the percentage of women
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Assume that women's heights are normally distributed with a mean of 63.6 and a standard deviation of 2.5 a) If 90 woman is randomly selected, find the probability that they have a mean height between 62.9 and 64.0 inches.
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The heights of women aged 20 to 29 follow approximately the N (64, 4) distribution. Men the same age have heights distributed as N (69.8, 1.1). What percent of young women are taller than the mean height of young men?
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A survey found that women’s heights are normally distributed with mean 63.4 in and standard deviation 2.5 in. A branch of the military requires women’s heights to be between 58 in and 80 in. a. Find the percentage of women
asked by Angie on August 4, 2014 
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The heights of women in a certain population have a Normal distribution with mean 64 inches and standard deviation 3.5 inches. We select three women at random from this population. Assume that their heights are independent. Find
asked by Sarah on November 20, 2016 
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A survey found that women's heights are normally distributed with mean 63.5 in. and standard deviation 2.3 in. The survey also found that men's heights are normally distributed with a mean 68.7 in. and a standard deviation 2.8.
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Suppose the heights of women aged 20 to 29 follow approximately the N(66.7, 2.4) distribution. Also suppose men the same age have heights distributed as N(70.5, 2.2). What percent (± 0.1) of young men are shorter than average
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