a police van moving on a highway with a speed of 30 kmph fired a bullet at a thief car speeding away in the same direction with a speed of 192kmph. if the muzzle speed of the bullet is 150 m per sec. the speed eith which the bullet hit the thief car is
Vo = 30km/h = 30,000m/3600s = 8.33 m/s.
Vc = 192km/h = 192,000m/3600s = 53.3 m/s.
Vm = 150 m/s.
V = Vo - Vc + Vm
To determine the speed at which the bullet hits the thief car, we need to calculate the relative velocity between the police van and the thief car.
Relative velocity is the difference in velocities between two objects.
Given:
Speed of the police van (V1) = 30 km/h = 30,000 m/3600 s = 8.33 m/s (converted from km/h to m/s)
Speed of the thief car (V2) = 192 km/h = 192,000 m/3600 s = 53.33 m/s (converted from km/h to m/s)
Muzzle speed of the bullet relative to the police van (V3) = 150 m/s
The relative velocity between the police van and the thief car (Vr) is given by:
Vr = V2 - V1
Vr = 53.33 m/s - 8.33 m/s
Vr = 45 m/s
Since the bullet is fired from a stationary position on the police van, its velocity relative to the thief car will be equal to the relative velocity between the police van and the thief car.
Therefore, the speed at which the bullet hits the thief car is 45 m/s.