University of jos,physics

A man walks 3m north then 4m east.calculate his displacement from the starting point.

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  1. distance = sqrt (3^2 + 4^2) = 5

    sin angle north of east = 3/5 = 0.6

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  2. sqrt (3^2 + 4^2) ...pls break this down, don't understand how its equal to 5. Thanks

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