
I've did the calculations, and I get
20sqrt symbol a^39posted by Christiaan

do you mean 20sqrt symbol a^9
posted by Chris

^5 sqrt symbol a^6 = a^(6/5)
and ^4 sqrt symbol a^3 = a^(3/4)
a^(6/5)*a^(3/4) = a^((6/5)+(3/4))
= a^(39/20) = ^20sqrt symbol a^39posted by Christiaan
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