Pre-calculus

Equation of the parabola with the vertex (0,3), axis parallel to OX, passing through (4,9)

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  1. x = a(y-3)^2 + 0
    but (4,9) lies on it, so
    4 = a(9-3)^2 + 0
    4 = 36a
    a = 1/9

    x = (1/9)(y-3)^2 is your equation.

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