# math

how many committee of five people can be chosen from 20 men and 12 women if a) exactly three men must be on each committee
b) at least four women on each committee

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1. Ahh, I see you fixed the problem from your earlier post.

a) 20 men, 12 women, choose 5, with exactly 3 men
= C(20,3) x C(12,2)
= 2053(66)
= 135498

b) at least 4 women
---> 4 women or 5 women

= C(20,1) x C(12,4) + C(20,0) x C(12,5)
= 20(495) + 1(792)
= 10692

check my arithmetic

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