Prealgebra/probability

A coin is tossed three times. Use a tree diagram to find the number of possible outcomes that could produce exactly two heads.

I don't know how to write out a tree diagram on here, but I think this one is heads -> heads, tails -> heads, heads -> tails?

A quarter and a penny are tossed. Then an eight sided die is rolled. How many possible outcomes are there?

I'm getting 32 for this one, but I'm not sure if I'm doing it right? 2*2*8?

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  1. Oops, I meant to write heads, heads, tails. Heads, tails, heads. Tails, tails, heads. Although it looks to me that there could be more combinations?

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  2. tails, tails, heads does NOT work
    H H T
    H T H
    T H H

    Quarter, Penny could be
    H H
    H T
    T H
    T T

    that is four, 8 now for each so 32 so I agree

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