chemistry

Calculate the pH of a solution obtained by mixing of 100 mL of a 10-3 M and 50 mL of a 10-2 M solution of CH3COONa.

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  1. CH3COOH = HAc.
    Calculate M of the solutions. millimols of each.
    mmols = mL x M = 100 mL x 10^-3 = 0.1
    mmols = 50 x 10^-2 = 0.5
    Total = 0.6
    M = mmols/mL = 0.6/150 mL = approx 0.004
    .....Ac^- + HOH --> HAc + OH^-
    I...0.004............0.....0
    C....-x..............x.....x
    E..0.004-x...........x.....x

    Kb for Ac^- = (Kw/Ka for HAc) = (x)(x)/(0.004-x). Solve for x = (OH^-) and convert to pH.

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