physics

tad drops a cherry pit out the car window 1 m above the ground while traveling down the road at 18 m/s.
a.how far, horizontally, from the initial dropping point will the pit hit the ground?
b. if the car continues to travel at the same speed, where will the car be in relation to the pit when it lands?

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asked by Bailey
  1. b is really easy. If there is no air friction, both the car and the pit continue at the same horizontal velocity and the pit lands right under the window.

    Now part A
    how long to fall 1 meter?
    0 = 1 + 0 - 4.9 t^2
    t^2 = 1/4.9
    t = sqrt (1/4.9)
    t = .452 s
    how far does it go in .452 s at 18 m/s?
    18*.452 = 8.13 meters

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    posted by Damon
  2. thanks

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    posted by Bailey
  3. WHy is 1-0 in the eguation?

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    posted by Nina

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