Calculate how many joules of energy would be needed to take 2kg of ice at
-5 and turn it all to steam at 100 degees celcius?

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asked by kadian
  1. first do it all for 1 kg and multiply the answer by 2

    -5 to 0
    2000 J/kg K * 5 = 10,000 J

    melt = 334 *10^3 J = 334,000 J

    0 to 100
    4190 *100 = 419,000 J

    boil = 2256*10^3 = 2,256,000 J
    so for 1 kg 3,019,000 J
    so for 2 kg 6,038,000 J

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    posted by Damon

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