A rectangular compound has the dimensions 6m by 10m A square carpet is laid in the centre of the compound. the carpet is 3m by 3m. Find the part of the compound that is uncovered by the carpet.
(6*10)-(3*3)=60-9=51
51 square
(6 * 10) - (3 * 3) = _______ square meters
(6×10)-(3×3)
60-9=51
so, the part of the compound that is uncovered by the carpet is 51 square meters.
Yes.
Workers in a certain company are required to 8% of their salary into a social security fund.Mr Doe has a monthly sarary of GH¢22.00 How much does he pay into the fund every month? And every year?
8÷100×22=1.76
Monthly payment =22-1.76=20.24 so therefore he pay 20.24 in the fund every month. In every year =20.24×12=240
To find the part of the compound that is uncovered by the carpet, we first need to calculate the total area of the compound and then subtract the area of the carpet.
Step 1: Calculate the area of the compound
The compound has dimensions of 6m by 10m, so the total area of the compound can be found by multiplying these dimensions together:
Area = length × width
Area = 6m × 10m
Area = 60 square meters
Step 2: Calculate the area of the carpet
The carpet is a square with dimensions of 3m by 3m. To calculate the area of a square, we can multiply the length of one side by itself:
Area of the carpet = side length × side length
Area of the carpet = 3m × 3m
Area of the carpet = 9 square meters
Step 3: Calculate the uncovered part of the compound
To find the part of the compound that is uncovered by the carpet, we subtract the area of the carpet from the total area of the compound:
Uncovered area = Total area of the compound - Area of the carpet
Uncovered area = 60 square meters - 9 square meters
Uncovered area = 51 square meters
So, the part of the compound that is uncovered by the carpet is 51 square meters.