In a first semester unit there are four tests each of equal weight i.e. each worth 25%. Your average on the first three tests has been 62%. You need to get an overall average of 65% to proceed to the second semester.
What percentage should you try to get on the fourth test?
Please show your work.
looks rather straightforward ...
(62+62+62+x)/4 = 65
186+x = 260
x = 74
Thanks Reiny
To determine the percentage you need to score on the fourth test, we can set up an equation.
Let X be the score on the fourth test.
The average of the first three tests is 62%:
(62 + 62 + 62) / 3 = 62
The overall average should be at least 65%:
(62 + 62 + 62 + X) / 4 ≥ 65
Now, let's solve for X:
(62 + 62 + 62 + X) / 4 ≥ 65
(186 + X) / 4 ≥ 65
Multiply both sides by 4 to eliminate the fraction:
186 + X ≥ 260
Subtract 186 from both sides:
X ≥ 260 - 186
X ≥ 74
Therefore, you need to score at least 74% on the fourth test in order to achieve an overall average of 65% and proceed to the second semester.
To determine the percentage you need to achieve on the fourth test, you can use the following formula:
Desired Average = (Sum of test scores + Fourth test score) / Total number of tests
In this case, we know that the desired average is 65% and there are four tests in total. The sum of the test scores of the first three tests is 62% x 3 = 186%.
Now, let's substitute the values into the formula and solve for the fourth test score:
65% = (186% + Fourth test score) / 4
To isolate the Fourth test score, we will first multiply both sides of the equation by 4:
260% = 186% + Fourth test score
Next, subtract 186% from both sides:
Fourth test score = 260% - 186%
Fourth test score = 74%
Therefore, you need to score at least 74% on the fourth test to achieve an overall average of 65% and proceed to the second semester.