Quadratic Formula
2x^2- 4x-3=0
My answer is (2±√10)/2 or (2√10)
Hmm....you seem pretty accurate to me ^-^
surely you are not saying that those two answers are equivalent.
(2±√10)/2
is the correct solution.
If you try plugging in 2√10 you will see that it does not do the job.
To find the roots of the quadratic equation 2x^2 - 4x - 3 = 0 using the quadratic formula, follow these steps:
1. Identify the values of a, b, and c from the quadratic equation in the form of ax^2 + bx + c = 0. In this case, a = 2, b = -4, and c = -3.
2. Substitute these values into the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a).
3. Now, plug in the values from the equation:
x = (-(-4) ± √((-4)^2 - 4 * 2 * (-3))) / (2 * 2).
Simplifying, we have x = (4 ± √(16 + 24)) / 4.
Further simplification gives x = (4 ± √40) / 4.
4. Simplify the square root: √40 = √(4 * 10) = 2√10.
5. Divide both the numerator and denominator by 4: (4 ± 2√10) / 4.
6. Simplify the fraction by canceling out the common factor: (2 ± √10) / 2.
Therefore, the roots of the quadratic equation 2x^2 - 4x - 3 = 0 are (2 ± √10) / 2, or you can also write it as (2√10) / 2.