science

3×10^18 photons of a certain light radiation are found to produce 1.5 j of energy. calculate the wavelength of light radiation

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  1. E=nhc/lamda
    >1.5= 3*10^18 * 6.626*10^-34 * 3*10^8/ lamda(wavelength)

    Therefore wavelength =3.973*10^-7

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  2. What the hell is this answer kha se copy mara h yrrr

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  3. E= nhc/ lambda
    1.5= 3×10^18 × 6.626×10^-34 × 3×10^8 / lambda
    Lambda= 9×10^26 × 6.626×10^-34
    ÷ 1.5
    Lambda = 39.75×10^-8 = 3975 Å

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  4. Question

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  5. Calculate the wavelength & the period of a blue light wit a energy 5 X 10^-19 J

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  6. E= nhc/ lambda
    1.5= 3×10^18 × 6.626×10^-34 × 3×10^8 / lambda
    Lambda= 9×10^26 × 6.626×10^-34
    ÷ 1.5
    Lambda = 39.75×10^-8 = 3975 Å

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