If you have a properly adjusted hot flame, which is pale blue with three distinct comes, what is observed if the GAS CONTROL valve is slightly closed versus what's observed if the AIR CONTROL valve is slightly closed? Please Explain.

the flame stays the same.

If the GAS CONTROL valve is slightly closed in a hot flame with a pale blue color and three distinct cones, the flame will become smaller and less intense. This occurs because the restricted flow of gas results in a reduced amount of fuel being combusted, leading to a decrease in heat output. The flame may also become slightly more yellow in color due to incomplete combustion.

On the other hand, if the AIR CONTROL valve is slightly closed in the same hot flame, the flame will become larger and more aerated. By restricting the flow of air, the ratio of gas to air becomes imbalanced, resulting in a fuel-rich mixture. This excess fuel causes the flame to expand, creating a larger flame with a more vibrant blue color. However, the flame may become unstable and flicker due to the insufficient amount of air necessary for complete combustion.

In summary, slightly closing the GAS CONTROL valve reduces the flame's size and intensity, while slightly closing the AIR CONTROL valve increases the flame's size and creates a more fuel-rich environment.

Instead of posting to get my opinion why don't you OBSERVE this in the lab yourself. Then you will know.