A mortar shell needs to be dropped into a bunker at an angle of 80 degree from level ground. The bunker is 100 yards away. How much velocity must the shell leave the cannon to accomplish this task?

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  1. If same height at both ends, symmetric parabolic path.

    Goes 100 yards? I guess I use obsolete units, 300 feet and g = 32 ft/s^2

    Vi = V sin 80 = .984 V
    u = V cos 80 = .174 V

    300 feet = u t
    300 = .174 V t

    how long does it take?
    h = Vi t - 16 t^2
    h = 0 at start and finish
    16 t^2 -Vi t = 0
    t (16 t-Vi) = 0
    t at target = Vi/16

    Vi = .984 V
    so t = .0615 V
    300 = .174 V (.0615 V)
    V^2 = 28034
    V = 167 feet/second

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