Ask questions and get helpful responses.

math

In a course a student's final exam is weighted as heavily as his mid term exam.if a student receives a score of 84 on his final exam 90 on his midterm,what is the average for the course?

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
  1. since they are of equal weight, their average is just the arithmetic average of the two scores: 87

    Why do I suspect that the problem was misstated?

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  2. (84 + 90) / 2 = ?

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
    👤
    Ms. Sue
  3. The final exam is weighed the same as the mid term exam. Therefore, you can add the two numbers and divide by 2.

    84 + 90 = 174

    174/2 = 87 (answer).

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  4. In a course a student's final exam is weighted twice as heavily as his mid term exam.if a student receives a score of 84 on his final exam 90 on his midterm,what is the average for the course?
    as final exam is weighted twice then
    84*2=168
    then 168+90=258
    the average
    258/3=86...is the ans right?

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  5. that looks better.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Respond to this Question

First Name

Your Response

Still need help? You can ask a new question.