Pre-Calculus

How do I solve: sin theta = -1 for all real values of theta?

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asked by Mary
  1. sin theta = -1 for 3 pi/2 and every full circle (2 pi) after that
    so
    theta = 3 pi/2 + 2 pi n
    for n = 0 to oo

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    posted by Damon

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