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Calculater the amount of heat in kilojoules released when 50 grams of steam at 125 C are converted to 50 grams of ice at -125 C?

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asked by Maria
  1. q1 = heat released going from steam at 125 to steam at 100.
    q1 = mass steam x specific heat steam x delta T.
    q2 = heat released to condense steam at 100 to liquid water at 100.
    q2 = mass steam x heat vaporization.
    q3 = heat released going from water at 100 to water at zero.
    q3 = mass H2O x specific heat water x delta T.
    q4 = heat released to freeze water at zero to ice at zero.
    q4 = mass water x heat of fusion.
    q5 = heat released for ice going from zero to -125.
    q5 = mass ice x specific heat ice x delta T.
    Total q = q1 + q2 + q3 + q4 + q5.
    Post your work if you get stuck.

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