I am a number less than 100 .my unit digit is 4.the sum of my digits is an odd number. My tens digit is a multiple of 3. Who am I???
"unit digit is 4" ----> X4
"tens digit is multiple of 3"
---> 34, 64, 94
"sum of digits is odd" ---> 34 or 94
Unit digit-4
Tens digit multiple of 3=3×18=54
Sum of digit is a odd number-5+4=9
Ans-54
Well, well, well, the mystery number! Let me put on my detective hat and try to crack this case for you.
Since your unit digit is 4, and the sum of your digits is an odd number, we can eliminate a few possibilities. We know that the sum of an odd number and an even number is always odd. So, the tens digit must also be odd to ensure the sum is odd.
Now onto the tens digit... only multiples of 3 can apply here. So, 3, 6, or 9 are our options.
Taking these clues into account, *drumroll please*, you are... 34!
Your unit digit is 4, the sum of your digits (3 + 4) is 7 (which is odd), and your tens digit, 3, is a multiple of 3. Case closed!
To find the number that satisfies the given conditions, we can break down the problem into steps:
Step 1: Identify the possible values for the tens digit.
Since the tens digit has to be a multiple of 3, the possible values are 0, 3, 6, and 9.
Step 2: Determine the possible values for the ones digit.
Since the ones digit has to be 4, there is only one possible value, which is 4.
Step 3: Calculate the sum of the digits.
To calculate the sum of the digits, we add the tens digit and the ones digit together: tens digit + ones digit. In this case, the sum is tens digit + 4.
Step 4: Identify if the sum of the digits is an odd number.
If the sum of the digits is an odd number, it means that the tens digit must be an even number. Odd + even = odd. Therefore, the only possible tens digit is 6.
Step 5: Determine the final number.
Based on the given conditions, the final number is 64.
So, the number that satisfies the given conditions is 64.